Question

test dimensionally that

${v}^2 - {u}^2 = 2as$​

Answer 1

Answer:

let's solve it one by one we know that dimensional formulae of velocity is L/T

so ${v}^2= {L/T}^2$

${v}^2 = {L}^2 {T}^-^2$

${u}^2= {L/T}^2$

${u}^2 = {L}^2 {T}^-^2$

${a}{s}= {L/T}^2$

${a}{s} = {L}^2 {T}^-^2$

Answer 2

Answer:

There are three terms in this equation V², U² and 2 as.

If these three terms are equal then the equation may be correct.

⟼${[ {v}^{2}] } = {( \frac{L}{T}) }^{2} = {L}^{2} {T}^{ - 2}$

⟼${[ {u}^{2}] } = {( \frac{L}{T}) }^{2} = {L}^{2} {T}^{ - 2}$

and ⟼${[2as]} = [a][s] = ( \frac{L}{ {T}^{2} } )L = {L}^{2} {T}^{ - 2}$

Thus, The Equation may be correct.

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