Question

TEST I-A: Given the center and radius of a circle, find the standard form of equation of a circle
Show your solutions.

1. Center: (3, 5) radius= 4
2. Center: (0, 0) radius= 8
3.center: (-4, 5) radius= 7
4.center (0, 0) radius=
$2 \sqrt{5}$




TEST I-B: Find the general equation of the circle given its center and radius.Show your sołutions
(5 points each)

5. center:(-4,5) radius=6

6. Center:(-5,-8) radius= 11

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Answer 1

Answer:

1.(x-3)²+(y-5)²=16

x²+y²-6x-10y+18=0

2.x²+y²=64

x²+y²-64=0

3.(x+4)²+(y-5)²=49

x²+y²+8x-10y-8=0

5.(x+4)²+(y-5)²=36

x²+y²+8x-10y+5 =0

6.(x+5)²+(y+8)²=121

x²+y²+10x+16y-32=0