Question

Test of divisibility by 3 and 9 A)99999

Answer 1

Answer:

divisibility rule for 3 : the sum of digits of the number must be a multiple of 3 . For example : the number is 3411. The sum of digits 3+4+1+1= 9 and 9 is a multiple of 3.[3x3=9] Hence,3411 is divisible by 3.

Divisibility rule for 9 : The sum of digits of the number must be a multiple of 9. For example : The number is 495. The sum of digits 4+9+5=18 and 18 is a multiple of 9. [9x2=18]. Hence,495 is divisible by 9.

Step-by-step explanation:

If you want to check the divisibility for 9999,

For 3 : 9+9+9+9=36 , 36 is a multiple of 3.[3x12=36] . Hence,9999 is divisible by 3.

For 9 : 9+9+9+9=36 , 36 is a multiple of 9[9x4=36]. Hence,9999 is divisible by 9.

Answer 2

Answer:

divisibility rule for 3 : the sum of digits of the number must be a multiple of 3 . For example : the number is 3411. The sum of digits 3+4+1+1= 9 and 9 is a multiple of 3.[3x3=9] Hence,3411 is divisible by 3.

Divisibility rule for 9 : The sum of digits of the number must be a multiple of 9. For example : The number is 495. The sum of digits 4+9+5=18 and 18 is a multiple of 9. [9x2=18]. Hence,495 is divisible by 9.

Step-by-step explanation: