test the condition of integrability and solve (yz+2x)dx+(zx-2z)dy+(xy-2y)dz=0
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Answer:
xyz+x2−2yz=c
(yz+2x)dx+(zx−2z)dy+(xy−2y)dz=0
⇒yzdx+zxdy+xydz+2xdx−2(zdy+ydz)=0
⇒d(xyz)+2xdx−2d(yz)=0
Integrating xyz+x2−2yz=c
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Step-by-step explanation:
equation is integrability
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