Math, asked by sudhanagpal367, 2 months ago

test the condition of integrability and solve (yz+2x)dx+(zx-2z)dy+(xy-2y)dz=0​

Answers

Answered by mangalakshmi0065
0

Answer:

xyz+x2−2yz=c

(yz+2x)dx+(zx−2z)dy+(xy−2y)dz=0

⇒yzdx+zxdy+xydz+2xdx−2(zdy+ydz)=0

⇒d(xyz)+2xdx−2d(yz)=0

Integrating xyz+x2−2yz=c

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Answered by shreedevishreedevi00
0

Step-by-step explanation:

equation is integrability

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