Math, asked by ashadsheikh3146, 10 months ago

Test the convergence of , sign of integration limit 0 to infinity dx/1+x²sin²x

Answers

Answered by IamIronMan0
0

Answer:

 \lim_{x \to  \infty }  \frac{1}{1 +  {x}^{2}  \sin {}^{2} (x) }  =  \frac{1}{ \infty }  = 0

So it converges

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