Question

Test the divisibility of 23,648 by 3, 8 and 10

Who give this ans. Marked brainliest. ​

Answer 1

Answer:

2+3+6+4+8=23 is not divisible by 3.

648÷8= 81 so it is divisible by 8

2+6+8= 16

3+4=7

16-7=9 not divisible by 11

Step-by-step explanation:

To test the divisibility of 23648 by 3,

Add all the digits and see if the sum is divided by 3 or not.

In this case,

2+3+6+4+8=23 which is not divisible by 3 and hence 23648 is not divisible by 3.

In dividing 23648 by 8 by divisibility rule,

If the last three digits is divisible by 8, it is divisible by 8.

Here, 648 which is divisible by 8 and hence 23648 is divisible by 8.

In dividing 23648 by 11 by divisibility rule,

The difference between the sum of digits at even places and the sum of the digits at odd places is either 0 or divisible by 11, then it is divisible by 11.

Here, 8+6+2=16 and 4+3=7 . Difference = 16-7=9. Hence 23648 is not divisible by 11.

Thank you for teasing my brain.