Math, asked by bhagwanadevi7, 7 months ago

test the divisibility of 72138 by ( 2'3,4,5,6,7,8,9,10,11)​

Answers

Answered by tejavaththavur41
1

2: divisible by 2[last 2 digits should be 2,4,6,8,0]

3:7+2+1+3+8=21[21 is multiple of 3]

4:38/4 not exactly divisible by 4[last 2 digits should be multiple of 4]

5:not divisible by5[ones place should be 0&5]

6:divisible by 6[number should be divisible by 2 &3]

8:138/8 not exactly divisible by 8[last 3 digits should be divisible by 8]

9:7+2+1+3+8=21[21 is not multiple of 9 so it 9s not divisible by 9]

10:not divisible by 10[ones place should be 0]

11:7+1+8=2+3;16=5 : not equal : is not divisible by 11

[sum of odd places=sum of even places]

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