Question

Test the divisibility of 8521 by the numbers 3, 6, 5, 10 using Divisibility rules.​

Answer 1

Answer:

here given number is 8521

sum of digits=8+5+2+1=16 which is not divisible by 3

since 8521 is not divisible by 3 it is not divisible by 6 also

this number can be divisible by 5 if 0 or 5 is in the last digit but here it is 1 therefore 5 is also not divisible

it can be divisible by 10 if last digit is zero but here it is 1

therefore the number is not divisible by 3,6,5 or 10

Answer 2

Step-by-step explanation:

Divisibility of 3:- A no is divisible by 3 if it's sum is divisible by 3.

8521= 8+5+2+1

       =16 =1+6

       =7. => Not divisible by 3.

Divisibility of 6:- A no is divisible by 6 if it is divisible by 2 and 3.

also, a no is divisible by 2 if the last digit of it is even.

8521= last digit- 1 => Not divisible by 2.

Hence, 8521 is neither divisible by 2 nor by 3, and so not divisible by 6.

Divisibility of 5:- A no is divisible by 5 if its last  digit is 5 or 0.

8521= last digit- 1=> Not divisible by 5.

Divisibility of 10:- A no is  divisible  by 10 if it ends with 0.

8521=> not divisible by 10.