Question

test the divisibility of 962731 number by 11
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Answer 1

very easy you can test within minutes

Divisiblity law by 11:

If the difference of 'sum of its digits at odd places' and 'sum of its digits at even places' is either 0 or a number divisible by 11.

Example : 4832718 is divisible by 11, since:

(Sum of digits at odd places) and (sum of digits at even places)

= (8+7+3+4)-(1+2+8) = 11

so for 962731

(9+2+3)-(6+7+1)

== 14 - 14

= 0 (proved : it is divisible by 11)

Answer 2

Answer:

Yes, it is divisible

Explanation:

Here an easy way to test for divisibility by 11. Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number.

So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.

Now, 962731, the alternating sum of digits is 9-6+2-7+3-1=3, which is divisible by 11, so, the number is divisible by 11.