Question

test the divisibility of the following by 2,3,4,5,6,7,8,9,10 and 11 ( Write yes or no) 996
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Answer 1

Divisibility test [996]

For 2

The digit at ones place should be even number.

→ 996 = Here 6 is even number.

Hence 996 is divisible by 2 .

For 3

Sum of all digits should be divisible by 3 .

→ 996 = 9+9+6 → 24

24 is divisible by 3 .

Hence 996 is divisible by 3 .

For 4 .

The last two digits of number should be divisible by 4.

→ 996 → 96 is divisible by 4 with quotient 24 .

Hence 996 is divisible by 4 .

For 5

Last digit should be either 0 or 5

→ 996 → last digit is neither 0 nor 5 .

Hence 996 is not divisible by 5 .

For 6 .

Number should be divisible by 2 and 3.

→ 996 → So it's divisible by 996 .

Hence 996 is divisible by 6 .

For 7 .

For it follow the steps -

Take off the last digit - 99 . ( we removed 6 )

Double the removed digit → 12 .

Substracting from remaining number .

→ 99-12 = 87 .

Now 87 is not divisible by 7 .

Hence 996 is not divisible by 7.

For 8.

Last 3 digits should be divisible by 8

→ 996 → not Divisible by 8 .

For 9 .

Sum of all digits should be divisible by 9.

→ 996 → 9+9+6 = 24

24 is not divisible by 9 .

Hence 996 is not divisible by 9 .

For 10 .

The ones place digit should be zero

→ 996 → ones place digit is 6.

Hence 996 is not divisible by 10 .

For 11.

Difference of sum of even place digits and odd place digit should be either 0 or divisible by 11 .

→ 996 → odd place = 9+6 = 15 , even place = 9

Difference = 15-9 = 6

Hence 996 is not divisible by 11 .

Answer 2

no it is not disible by 996 it will disible by 11