Math, asked by manitagrawalgzp007, 1 month ago

Test the divisibility of the given numbers by 2, 3, 4, 5, 6, 8, 9, 10. (4 marks) a) 4, 813 b) 6, 225​

Answers

Answered by AMMOHAMMEDRABEEH
0

Answer:

a) The given number is 4813

The one’s digit of 4813 is 3 which is not an even number

Therefore, 4813 is not divisible by 2

The sum of the digits of 4813 = 4 + 8 + 1 + 3 = 16

16 is not divisible by 3

Therefore, 4813 is not divisible by 3

The last two digit of 4813 is 13

13 is not divisible by 4

Therefore, 4813 is not divisible by 4

The one’s digit of 4813 is 3 which is neither 0 nor 5

Therefore, 4813 is not divisible by 5

4813 is neither divisible by 2 nor by 3

Therefore, 4813 is not divisible by 6

The last three digits of 4813 is 813

813 is not divisible by 8

Therefore, 4813 is not divisible by 8

The sum of the digits of 4813 = 4 + 8 + 1 + 3 = 16

16 is not divisible by 9

Therefore, 4813 is not divisible by 9

The one’s digit of 4813 is 3 which is not 0

Therefore, 4813 is not divisible by 10

b) The given number is 6225

The one’s digit of 6225 is 5 which is not an even number

Therefore, 6225 is not divisible by 2

The sum of the digits of 6225 = 6 + 2 + 2 + 5 = 15

15 is divisible by 3

Therefore, 6225 is divisible by 3

The last two digit of 6225 is 25

25 is not divisible by 4

Therefore, 6225 is not divisible by 4

The one’s digit of 6225 is 5

Therefore, 6225 is divisible by 5

6225 is divisible by 3 but not by 2

Therefore, 6225 is not divisible by 6

The last three digits of 6225 is 225

225 is not divisible by 8

Therefore, 6225 is not divisible by 8

The sum of the digits of 6225 = 6 + 2 + 2 + 5 = 15

15 is not divisible by 9

Therefore, 6225 is not divisible by 9

The one’s digit of 6225 is 5 which is not 0

Therefore, 6225 is not divisible by 10

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