Question

test the divisiblity by 2 and 3 of the number 120​

Answer 1

Answer:

Step-by-step explanation:

The divisibility test of 2 is whether the last number is an even number.

Since the last digit of 120 is 0, it is even thus being divisible by 2.

The divisiblity test of 3 is when the sum of all the digits in that number is divisible by 3.

The sum of 120 is 3 which is obviously divisible by 3.

Thus 120 is divisible by 2 and 3.

Hope it helps you.

Plz mark as brainliest :)

Answer 2

Answer:

by 3:  1+2+0=3 is divible by 3 and by 2: since 120 is a multiple of 2

Step-by-step explanation: