Math, asked by muhammadanshif954, 2 months ago

test whether the following numbers are divisible by 2 , 3 5 and 10:

a) 3458 b) 7995

please say me this answer then i will mark u has brain list

Answers

Answered by yashgauniyal2007
0

divisible by 2

a) 3458- Yes it is divisible by 2 because the last number is even number

b)- 7995- no it is not divisible by 2 because the last number is not even number

divisible by 3

a)- 3 + 4 + 5 + 8 = 20

it is not divisible by three because if we are adding the digits the answer is not divisible by 3

b)- 7 + 9 + 9 + 5 = 30

yes it is divisible by 3 because if we are adding the digit the answer is divisible by 3

divisible by 5

a)- 3458- No this number is not divisible by 5 because the last digits are neither 5 not 0

b)- 7995- Yes this number is divisible by 5 because the last digits is 5

divisible by 10

a)- 3458- No this number is not divisible by 10 because the last number is not 0

b)- 7995- No this number is not divisible by 10 because a last number is not zero

Answered by chandrasekharvemula
0

Answer:

3458 is divisible by 2; 7995 is divisible by 3 and 5.

Step-by-step explanation:

3458 is divisible by 2 because the ending digit is even.

3458 is not divisible by 3 because 3+4+5+8=20 which is not divisible by 3.

3458 is not divisible by 5 because the ending digit is not 5 or 0.

3458 is not divisible by 10 because the ending digit is not 0.

7995 is not divisible by 2 because ending digit is not even.

7995 is divisible by 3 as 7+9+9+5=30 which is divisible by 3.

7995 is divisible by 5 as endling digit is 5.

7995 is not divisible by 10 as ending digit is not 0.

Similar questions