Math, asked by sreevidya8446, 11 months ago

Test whether the given numbers are perfect cubes or not.
(i) 243
(ii) 516
(iii) 729
(iv) 8000
(v) 2700

Answers

Answered by TooFree
116

Perfect cubes ⇒ When the number can be represented in the form of another integer(s) with exponents in the multiples of 3s


Find the prime factors:

(i) 243  = 3⁵ (exponent ≠ multiple of 3s≠ not a perfect cube)

(ii) 516 = 2² x 3 x 43 (exponent ≠ multiple of 3s≠ not a perfect cube)

(iii) 729 = 3⁶ (exponent = multiple of 3 = perfect cube)

(iv) 8000 = 2⁶ x 5³ (exponent = multiple of 3 = perfect cube)

(v) 2700 = : 2² x 3³ x 5²(exponent ≠ multiple of 3s≠ not a perfect cube)


Answer: 729 and 8000 are perfect cubes

Answered by yesasawinivenati
29

Answer:

1: not a perfect cube

2: not a perfect cube

3: perfect cube

4: perfect cube

5:not a perfect cube

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