Math, asked by Nishthashree3804, 19 days ago

Teta=6t+3t×t+4t×t×t
The angular acceleration of fly wheel after 2sec

Answers

Answered by iyervinayak01
1
Differentiate d(theta)/dt=6+6t+12t^2
Again differentiate d^2(theta)/dt^2=6+24t
Now angular acceleration is d^2(theta)/dt^2 and t=2 sec
So angular acceleration is=6+24(2)=54 rad/sec^2
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