Question

- Tetrachloromethane, CCl4 is produced from the substitution reaction between methane and
chlorine gas. If the rate of formation of CC14 is 0.05 mol dm' min', what is the rate of
disappearance of chlorine gas?​
A 0.0125 mol dm^-3 min^-1
B 0.0500 mol dm^-3 min^-1
C 0.100 mol dm^-3 min^-1
D 0.200 mol dm^-3 min^-1

Answer 1

Answer:

the answer is C

Explanation:

first you need to create the balance equation of the reaction

then you compare the moles from the general equation and from the experiment. the rate is based on 1 minute which you can ignore it since it is the same for rate of disappearance.

CH4 + 2Cl2 = CCl4 + 2H2

from general equation,

1 mol of CCl4 = 2 mol of Cl2

if 0.05 mol of CCl4 = x mol of Cl2