Biology, asked by anonymous14, 1 year ago

tetrahybrid plant produces fruits of 1 kg while minimum weight is 400 g. What will be the maximum weight of a fruit :- (1) 600 g (2) 1600 g (3) 1200 g (4) 1800 g
ans is 2 pleass expln

Answers

Answered by writersparadise
9

The correct answer should be the option 2 - 1600 g.


When the total number of present are recessive, then the minimum weight condition is achieved and if all the alleles are dominant, then the maximum weight condition is achieved.


Since it has been given that it is a tetrahybrid plant, the genes present will be AaBbCcDd.


The weight of the plant is 1 kg or 1000 g, i.e minimum weight (400 g) + weight caused by the 4 dominant alleles.


So, the weight of four dominant alleles =1000 g - 400 g = 600 g.


Therefore, the total weight due to the presence of 8 dominant alleles will be 


= 400 g + 2 x 600 g 


= 400 g+1200 g = 1600 g.

Answered by thewordlycreature
1

tetrahybrid plant produces fruits of 1 kg while minimum weight is 400 g. What will be the maximum weight of a fruit :- (1) 600 g (2) 1600 g (3) 1200 g (4) 1800 g

Answer: 2) 1600gm

Individuals who have two different alleles are said to be heterozygous at that locus. Many plants that have red flowers can have one allele for red color and another for white color. The externally observed characteristic of an individual is called the phenotype. The phenotype in a heterozygous individual is said to be the ‘dominant’ form of the gene and the trait that is suppressed is considered as the ‘recessive’ allele. In the example of flower color, the allele coding for red color is dominant over the one for white.

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