Question

$1 ^{2} + 2 ^{2} +3^{2} = \\ 5.99 + 4.32 - (16 + 4)^{2} = \\ (4 + 3) ^{2} - 16.99 = \\ 1.632 + 1.674 - 132.14 + 176 = \\ \frac{3}{2} + \frac{4}{3} + \frac{6}{2} = \\ (14)^{2} + 24.96 - 162 - 14 = \\ \frac{326}{14} + 24 = \\ \frac{4324}{12} = \\ \frac{1696}{41} = \\ 14 - 24 + 64 - 12 = \\ 1^{3} + {2}^{3} + {3}^{3} + {4}^{3} + {5}^{3} + =$
answer math?

Answer 1

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