Question

${1}^{2} + {2}^{2} + {3}^{2} + ... {x}^{2} = \frac{x(x + 1)(2x + 1)}{6} then {1}^{2} + {3}^{2} + {5}^{2} .... {19}^{2} =$
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Answer 1

Answer:

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Step-by-step explanation:

aap sabhi ko hardik badhai