Question

$1 {}^{2} + 2 {}^{2} + ........ + n {}^{2} = 1015$
then value of n​

Answer 1

$\huge \bf{ \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}}$

$\tt\implies\dfrac{1}{6} \: n(n + 1)(2n + 1) \: = 1015$

$\tt\implies\:(2n)(2n + 1)(2n + 2) \: = \: (28)(29)(30)$

$\tt\implies\:2n \: = \: 28$

$\tt\implies{\boxed {n \: \: = \: 14}}$

Answer 2

Hey Mate here is your answer ✌️