Question

$(1) (2 { }^{2} + 9)(2a {}^{2} + 5) \\ = x {}^{2} + (a + b)x + ab \: \\ (2a {}^{2} ) + (9 + 5)2a {}^{2} + (9)(5) \\ 4a { }^{2} + (14)2a {}^{2} + 45 \\ 4a {}^{2} + 28a {}^{2} + 45$
​

Answer 1

Answer:

Ok

Step-by-step explanation:

Solution

fXY(x,y)=∫∞−∞fXYZ(x,y,z)dz=∫1013(x+2y+3z)dz=13[(x+2y)z+32z2]10=13(x+2y+32),for0≤x,y≤1.

Thus,

fXY(x,y)=⎧⎩⎨⎪⎪13(x+2y+32)00≤x≤1,0≤y≤1otherwise

This can help you little bet