Question

$1 - 49(x + y)$
1 - 49 (X + y) whole square ​

Answer 1

Step-by-step explanation:

$1 - 49 {(x + y)}^{2} \\ \\ 1 - 49( {x}^{2} + {y}^{2} + 2xy) \\ \\ 1 - 49 {x}^{2} - 49 {y}^{2} - 98xy$

Answer 2

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$\rightarrow1 - 49 {(x + y)}^{2} \\ \\ \rightarrow 1 - 49( {x}^{2} + {y}^{2} + 2xy) \\ \\ \rightarrow1 - 49 {x}^{2}- 49 {y}^{2} - 98xy.$

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