Question

$(1.5 \times 10 {}^{11} m) \times( 3.5 \times 10 {}^{22}n ) \div m2 \: \: = \frac{6.67 \times 10 {}^{ - 11} nm {}^{2} }{kg {}^{2} } \times \: 6 \times {10}^{24} kg$
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Answer 1

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