Question

$1 - \cos( \alpha ) \times 1 + \cos( \alpha ) \times 1 + \cos( \alpha ) =$
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Answer 1

Answer:

Let P be a point at a distance r from the center of the dipole on the equatorial line, where the electric field is to be calculated. Let E1 be electric field intensity at P due to charge –q. Therefore, From right-angled triangle AOP, we have AP = √r2 + a2