Question

$(1 + cot ^{2} e). sin ^{2} e = 1 \\ \\ what \: isa \: answer \: this$
​

Answer 1

TO PROVE :–

$\\ \implies\bf(1 + cot ^{2} e). sin ^{2} e = 1$

SOLUTION :–

• Let's take L.H.S. –

$\\ \: \: = \: \: \bf(1 + cot ^{2} e). sin ^{2} e$

• We know that –

$\\ \implies\large \red{ \boxed{ \bf \cot( \theta) = \dfrac{ \cos( \theta) }{ \sin( \theta) }}}$

• So that –

$\\ \: \: = \: \:\bf \bigg[1 + \bigg\{ \dfrac{ \cos(e) }{ \sin(e)} \bigg \}^{2} \bigg]. sin ^{2} e$

$\\ \: \: = \: \:\bf \bigg[1 +\dfrac{ \cos^{2}(e) }{ \sin^{2}(e)}\bigg]. sin ^{2} e$

$\\ \: \: = \: \:\bf \bigg[\dfrac{\sin^{2}(e) + \cos^{2}(e) }{ \sin^{2}(e)}\bigg]. sin ^{2} e$

$\\ \: \: = \: \:\bf \bigg[\dfrac{\sin^{2}(e) + \cos^{2}(e) }{ \cancel{\{\sin^{2}(e) \}}}\bigg].\cancel{\{\sin^{2}(e) \}}$

$\\ \: \: = \: \:\bf\sin^{2}(e) + \cos^{2}(e)$

• We also know that –

$\\ \implies \large \red{ \boxed{\bf\sin^{2}( \theta) + \cos^{2}( \theta) = 1}}$

• So that –

$\\ \: \: = \: \:\bf1$

$\\ \: \: = \: \:\bf R.H.S.$

$\\ \: \: \: \: \large{ \underbrace{\bf Hence \: \: Proved}}$

Answer 2

omg very sryy but u won't get free points

nothing is free work hard to get everything

byee gbsdtc❥☺️❥☺️❥☺️❥

may u get horror drms