Question

$1 \div 1 = 0$
prove it​

Answer 1

Step-by-step explanation:

$a = b \\ a \times a = b \times a \\ {a}^{2} = ab \\ {a}^{2} - {b}^{2} = ab - {b}^{2} \\ (a + b)(a - b) = b(a - b) \\ a + b = b \\ 0 = 1 \\ \\ so \\ \frac{1}{1} = \frac{0}{1} = 0 \\ hence \: proved$

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