Math, asked by sweety33114, 9 months ago


1  \div 3 + 4i + 1 \div 3 - 4i

Answers

Answered by Anonymous
16

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1 \div 3 + 4i + 1 \div 3 - 4i

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 \frac{1}{3 + 4i}  +  \frac{1}{3 - 4i}

 \frac{1(3  - 4i) + 1(3 + 4i)}{ {3}^{2} -  {i}^{2}  }

 \frac{(3 - 4i) +( 3 + 4i)}{9 - ( -1 )}

 \frac{( {3})^{2} -  ({4i})^{2}  }{10}

 \frac{9 - ( - 16)}{10}

 =  \frac{25}{10}  =  \frac{5}{2}

Hope it helps you..!!!

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