Question

$1 \div ( \frac{1}{2} + \frac{1}{3} + 1 + \frac{1}{6} \div ( \frac{3}{4} - \frac{1}{3} ))$
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Answer 1

Answer:

$\frac{10}{48}$

Step-by-step explanation:

$1 \div ( \frac{1}{2} + \frac{1}{3} + 1 + \frac{1}{6} \div ( \frac{3}{4} - \frac{1}{3} ) \\ = 1 \div ( \frac{1}{2} + \frac{1}{3} + 1 + \frac{1}{6} \div ( \frac{9 - 4}{12} ) \\ = 1 \div ( \frac{1}{2} + \frac{1}{3} + 1 + \frac{1}{6} \div ( \frac{ 5}{12} ) \\ = 1 \div ( \frac{3 + 2 + 6 + 1}{6} \div \frac{5}{12} ) \\ = 1 \div ( \frac{12}{6} \times \frac{12}{5} ) \\ = 1 \div \frac{12}{2} \times \frac{4}{5} \\ = 1 \div \frac{48}{10} \\ = 1 \times \frac{10}{48} = \frac{10}{48}$

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