Question

$1 \div {x}^{2} + 3 = 1 \div 12$
please give me the answer of this question..​

Answer 1

Question :-

$\rm \dfrac{1}{x^{2} + 3} = \dfrac{1}{12} \: find \: x$

Taking Square of x to right side Numerator as we can do cross Multiplication so, only I am taking Square of x in Numerator right side and keeping 3 down only in left side denominator. So, that becomes :-

$\rm \dfrac{1}{3} = \dfrac{ {x}^{2} }{12}$

Now taking 12 to left side of equals so that it's help us to divide and How can we take it ? → As we can do cross Multiplication that's why we can do that

$\rm \cancel\dfrac{12}{3} = \dfrac{ {x}^{2} }{1}$

$\rm \: 4 = {x}^{2}$

Now if we do Square root in both side x will come

$\rm\sqrt{ \: 4 }= \sqrt{{x}^{2} }$

$\rm \: \bf 2 = \bf \: x$

or,

$\rm \: \bf X = \bf \: 2$

$\sf\therefore \: Value \: of \: x \: is \: \bf 2$

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