Question

$1. find \: the \: number \: from \: each \: of \: the \: foowing \: expanded \: forms \: \\ (1). \: 6 \times 10 {}^{3} + 5 \times 10 {}^{2} + 0 \times 10 + 6 \times 10 {}^{0}$
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Answer 1

Answer:

order to make class intervals even we need to add 0.5 and reduce 0.5 from class boundaries

1−5 = 0.5−5.5

6−10 = 5.5−10.5

11−15 = 10.5−15.5

so , lower boundary of class 11−15 = 10.5

Answer 2

Answer:

6,506

Step-by-step explanation:

6000 + 500 + 0 + 6 = 6,506 = 6.506×10³