Question

$(1 - \frac{a +b}{a - b} ) \div \frac{4a}{ {2a }^{2} - 2ab }$
show that
how to solve this​

Answer 1

Answer:

$(1-\frac{a+b}{a-b})$  ÷  $\frac{4a}{2a^{2}-2ab}$

$(\frac{a-b-a-b}{a-b})$ ÷  $\frac{4a}{2a^{2}-2ab}$

$\frac{-2b}{a-b}$ ÷  $\frac{4a}{2a(a-b)}$

$\frac{-2b}{a-b}$  ÷ $\frac{2}{a-b}$

on canceling 2 and a-b we have the final answer as -b