Question

$1. \: p(8 - 2) = 12$
$2. \: ( - 5)(z + 2) = - 4$
$3. \: 6(k - 3) = 8$

Answer 1

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$1. \: p(8 - 2) = 12$

$\therefore p(6) = 12$

$\therefore p = 12 \div 6$

$\green \Longrightarrow \blue{\fbox{p = 2}}$

$2. \: ( - 5)(z + 2) = - 4$

$\therefore - 5z - 10 = - 4$

$\therefore - 5z = - 4 + 10$

$\therefore - 5z = 6$

$\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }}$

$3. \: 6(k - 3) = 8$

$\therefore 6k - 18 = 8$

$\therefore 6k = 8 - 18$

$\therefore 6k = - 10$

$\therefore k = - \frac{10}{6}$

$\green \Longrightarrow \blue{ \boxed{ k = - \frac{5}{3} }}$

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Answer 2

$\huge\colorbox{lightgreen}{Answer}$

.p(8−2)=12\therefore p(6) = 12∴p(6)=12\therefore p1\div 6∴p=12÷6\begin{gathered} \green \Longrightarrow\blue{\fbox{p = 2}} \\ \\ \end{gathered} ⟹ p = 2

2. \: ( - 5)(z + 2) = - 42.(−5)(z+2)=−4\therefore - 5z - 10= - 4∴−5z−10=−4\therefore - 5z = - 4 + 10∴−5z=−4+10\therefore - 5z =6∴−5z=6\begin{gathered}\green \Longrightarrow \blue{ \boxed{ z = - \frac{6}{5} }} \\ \\ \\\end{gathered⟹ z=− 56