Math, asked by saivedanshgelly, 9 months ago


(1+tan theta +sec theta)(1+cot theta-cosec theta)

pls \: answer \: asap

Attachments:

Answers

Answered by parasbhumbak3
1

Answer is in the photo check it out...

HOPE IT WILL HELP☺

#STAY HOME #STAY SAFE

Attachments:
Answered by itzsecretgiggle18
2

Answer:

Answer:-

\red{\bigstar} Value is \large\underline{\boxed{\tt\purple{2}}}

• Given:-

\sf(1 + tan \theta \: + sec \theta)(1 + cot \theta \: - cosec \theta)

★ Basic Knowledge:-

\sf\pink{tan \theta = \dfrac{sin \theta}{cos \theta}}

\sf\pink{cot \theta = \dfrac{cos \theta}{sin \theta}}

\sf\pink{sec \theta = \dfrac{1}{cos \theta}}

\sf\pink{cosec \theta = \dfrac{1}{sin \theta}}

\sf\pink{sin^2 \theta + cos^2 \theta = 1}

• Solution:-

\sf(1 + tan \theta \: + sec \theta)(1 + cot \theta \: - cosec \theta)

\sf \bigg(1 + \dfrac{sin \theta}{cos \theta}+ \dfrac{1}{cos \theta} \bigg) \bigg(1+ \dfrac{cos \theta}{sin \theta} - \dfrac{1}{sin \theta} \bigg) \\

\sf \bigg(\dfrac{cos \theta + sin \theta + 1 }{cos \theta} \bigg) \bigg(\dfrac{sin \theta+ cos \theta - 1}{sin \theta} \bigg) \\

\sf \bigg(\dfrac{(sin \theta + cos \theta - 1)(cos \theta + sin \theta + 1)}{cos \theta . sin \theta} \bigg) \\

\sf \bigg(\dfrac{(sin \theta + cos \theta - 1)(sin \theta + cos \theta + 1)}{sin \theta . cos \theta} \bigg) \\

\sf \bigg(\dfrac{(sin \theta + cos \theta)^2 - 1^2}{sin \theta . cos \theta} \bigg) \\

\sf \bigg(\dfrac{sin^2 \theta + cos^2 \theta+ 2 sin cos \theta - 1}{sin \theta . cos \theta} \bigg) \\

\sf \bigg(\dfrac{1 + 2 sin cos \theta - 1}{sin \theta . cos \theta} \bigg) \\

\sf \bigg(\dfrac{2 sin \theta. cos \theta}{sin \theta . cos \theta} \bigg) \\

\large{\bf\green{2}} \\

Therefore, the value of \sf(1 + tan \theta \: + sec \theta)(1 + cot \theta \: - cosec \theta)

is 2.

Similar questions