Question

$1 \x. + 1 \y = 12 . 3 \x - 2 \y = 1$
​

Answer 1

Answer:

+

y

1

=12

x

3

−

y

2

=1

Substituting

x

1

=a and

y

1

=b in the above equations,

a+b=12...(1)

3a−2b=1...(2)

Multiplying equations (1) by 2 and solving with (2), we get

2a+2b=24...(3)

3a−2b=1

5a=25

a=

5

25

=5

Substituting, a=5 in equation (1),

a+b=12

5+b=12

b=12−5=7

Answer verified by Top

x

2

+

3y

2

=

16

1

:

x

3

+

y

2

=0

Study later

View solution

Solve the following system of equations:

8v=3u+5uv

6v−5u

Step-by-step explanation:

I hope this helps you

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Thank you

Answer 2

Answer: +

y

1

=12

x

3

−

y

2

=1

Substituting

x

1

=a and

y

1

=b in the above equations,

a+b=12...(1)

3a−2b=1...(2)

Multiplying equations (1) by 2 and solving with (2), we get

2a+2b=24...(3)

3a−2b=1

5a=25

a=

5

25

=5

Substituting, a=5 in equation (1),

a+b=12

5+b=12

b=12−5=7

 

x

2

+

3y

2

=

16

1

:

x

3

+

y

2

=0

Study later

View solution

Solve the following system of equations:

8v=3u+5uv

6v−5u

Step-by-step explanation:

I hope this helps you

make me as brainliest

Thank you