Math, asked by riya2073, 10 months ago


1 + x {2} \div x  {2} - 5x + 6 < 0

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Answered by Anonymous
2

 \frac{1 + x {}^{2} }{x {}^{2}  - 5x + 6 }  < 0 \\  =  > 1 + x {}^{2}  < 0 \\  =  > x {}^{2}  <  - 1 \\  =  > x <  \sqrt{ - 1}  \\  =  > x < i \:  \:  \\ i = imaginary \: number

Answered by Anonymous
0

Answer:

\begin{lgathered}\frac{1 + x {}^{2} }{x {}^{2} - 5x + 6 } < 0 \\ 1 + x {}^{2} < 0 \\ x {}^{2} < - 1 \\ x < \sqrt{ - 1} \\ x < i \: \: \\ \end{lgathered}

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