Question

$10 \div x + y + 2 \div x - y = 4 \\ 15 \div x + y - 5 \div x - y = - 2 \\ solve \: the \: following \:$
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Answer 1

number 1

$10 \div x + y + 2 \div x - y = 4$

$to \: find \: x - intercept \ \: zero \: substitute \: y = 0$

$10 \div x + 0 + 2 \div x - 0 = 4$

solve the equation x

$x = 3$

number 2

$15 \div x + y - 5 \div x - y = - 2$

$15 \div x + 0 - 5 \div x - 0 = 2$

$x = - 5$