Math, asked by abhishek44560, 8 months ago


100 x { }^{2}  - 20x + 1 = 0

Answers

Answered by arci
1

Answer:

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Attachments:
Answered by 007Boy
2

Given :-

100x {}^{2}  - 20x + 1 = 0 \\  \\

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

100 {x}^{2}  - 20x + 1 = 0 \\  \\ 100 {x}^{2}  - 10x - 10x + 1 = 0 \\  \\ 10x(10x - 1) - 1(10x - 1) = 0 \\  \\ (10x - 1) (10x - 1) = 0 \\  \\ (10x - 1) { }^{2}  = 0

Hence,

x =  \frac{1}{10}  \:  \:  \:  \:  \: ans

Extra information :-

  • An equation containing a single variable of degree 2. Its general form is ax^2 + bx + c = 0, where x is the variable and a, b, and c are constants (a ≠ 0).
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