Math, asked by psayushuskp, 11 months ago


100b  {}^{2}  - 60bc + 9c {}^{2}
factorise the following using identities ​

Answers

Answered by himangiagrawal15
5

Answer:

(10+3)²

(10+3)(10+3)

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Answered by acrocool06
20

Step-by-step explanation:

100b^{2}  - 60bc + 9 {c}^{2}  =  \\ 100 {b}^{2}  - 30bc - 30bc + 9 {c}^{2}  =

10b(10b  - 3c) - 3c(10b - 3c) \\  = (10b - 3c)(10b - 3c)

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