Question

$100x^{2} + 20x + 1 = 0$

Answer 1

Step-by-step explanation:

100x²+20x+1=0

100x²+10x+10x+1=0

10x(10x+1)+1(10x+1)

(10x+1)(10x+1)

X=-1/10 (or) -1/10

Another model:-

100x²+20x+1=0

ax²+bx+c=0

(comparing of both statements)

We get,

a=100,b=20&c=1

=b²±√4ac/2a

=100²±√4(100)(1)/2(100)

=10000±√400/200

=10000±20/200

=±10200/200

=±51

Hope it will help you

Answer 2

Solution :

$\mathsf{100x^{2} \:+ \:20x + \:1\: =\: 0}$

Using split the middle term method,

$\mathsf{100x^{2} \:+ \:10x \:+\:10x\:+ \:1\: =\: 0}$

$\mathsf{10x(10x\:+ \:1 )\:+\:1(10x\:+ \:1) \: =\: 0}$

( 10x + 1 ) ( 10x +1 ) = 0

10x +1 = 0, 10x + 1 = 0

x = - 1/10 or - 1/10

Hence, Roots are equal.