Question

$100x { }^{2} - 20x + 1 = 0$
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Answer 1

Answer:

${100x}^{2} - 20x + 1$

using :-

Factorisation

${100x}^{2} - 10x - 10x + 1 = 0$

$10x(10x - 1) - 1(10x - 1) = 0$

$(10x - 1)(10x - 1) = 0$

$10x - 1 = 0 \\10x = 1 \\ x = \frac{1}{10}$

$10x - 1 = 0 \\ 10x = 1 \\ x = \frac{1}{10}$

Hope it helps

Answer 2

Answer:

By factorisation

${100}x^{2} - 20x + 1 = 0 \\ = > {100x}^{2} - 10x - 10x + 1 = 0 \\ = > 10x(10x - 1) - 1(10x - 1) = 0 \\ = > (10x - 1)(10x - 1) = 0 \\ = > 10x - 1 = 0 \\ = > x = \frac{1}{10}$

And

10x-1=0

x=1/10