Math, asked by Anonymous, 1 year ago


102 ^3 \: evaluate \: using \: proper \: algebraic \: identity

Answers

Answered by Akshaymas
4
(100+2)³= 100³+2³+3×100²×2+3×100×2²

= 1000000+8+60000+1200

= 1,061,208.

the formula used is (a+b)³=a³+b³+3a²b+3ab².

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