Question

$11 \times 11 + \binom}{?}$
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Answer 1

Answer:

$multiply \: 11 \: and \: 11 \: to \: get \: 121 \\ \\ \frac{121}{12 - (13 - 12)} \\ \\ subtract \: 12 \: from \: 13 \: to \: get \: 1. \\ \\ 121 + \frac{11}{12 - 1} \\ \\ subtract \: 1 \: from \: 12 \: to \: get \: 11 \\ \\ 121 + \frac{11}{11} \\ \\ divide \: 11 \: by \: 11 \: to \: get \: 1. \\ \\ 121 + 1 \\ \\ add \: 121 \: and \: 1 \: to \: get \: 122 \\ \\ = > 122 \: \: is \: the \: answer$

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Answer 2

Step-by-step explanation:

$11 \times 11(11 \div (12 - 1))$

$= 121 + (11 \div 12 - 1)$

$= 121 + (11 \div 11)$

$= 121 + 1$

$= 122$