Math, asked by chhavi7357, 10 months ago


11 {x }^{2}  + 26x + 21

Answers

Answered by MrChauhan96
27

\bf\purple{\underline{\boxed{Question}}}

\:

\small\tt{11 {x }^{2} + 26x + 21}

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\bf\purple{\underline{\boxed{Solution}}}

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\tt{11x^{2}+26x+21}

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\small\tt{where\:\:,}

\small\tt{a\:=\:11}

\small\tt{b\:=\:26}

\small\tt{c\:=\:21}

\:

\small\tt{using\: formula\:\:D\:=\:b^{2}-4ac}

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\small\tt{\:=\:26^{2}-4\times11\times21}

\small\tt{\:=\:676\:-\:924}

\small\tt{D\:=\: -248}

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\small\tt{using\: formula\:\:}

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\tt{x\:=\:\frac{-b±\sqrt{ \ b^{2}-4ac}}{2a}}

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\tt{x\:=\:\frac{-(26)±\sqrt{-248}}{2\times 11}}

\tt{x\:=\:\frac{-26±\sqrt{ -248}}{22}}

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\small\tt{There\:are\:2\:possible\:values}

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\small\tt{1)\:\:Postive\:}

\tt{x\:=\:\frac{-26+\sqrt{ -248}}{22}}

\:

\small\tt{2)\:\:Negetive\:}

\tt{x\:=\:\frac{-26-\sqrt{ -248}}{22}}

\:

\bf\purple{\underline{\boxed{Thanks}}}

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