Math, asked by kishor2008, 8 months ago


15 {6 < 3 \sqrt[.]{?} }^{2}

Answers

Answered by Anonymous
10

Answer:

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Step-by-step explanation:

156 <  { 3\sqrt{x} }^{2}  \\  =  \frac{156}{3} <  { \sqrt{ x} }^{2} \\  =  { \sqrt{x} }^{2}  > 52 \\

So from here, we can clearly see that x must be greater than 7,as (7)^2=49.

So x (8,9,10.........n)

HOPE IT HELPS.

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