Question

$15j^{12}$ x $j^{-12}$ =

Answer 1

Answer:

15 is the answer

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Answer 2

Step-by-step explanation:

$15j ^{12} \times j ^{ - 12}$

$15j ^{12 - 12}$ ( law of indices)

$15j ^{0}$

$15 \times 1$ ( a^0 = 1 law of indices

$15$