Question

$16^{2} +(16-m)^2 = (16+m)^2$
find m.

Answer 1

Answer:

${16}^{2} + (16 - m) {}^{2} = (16 + m) {}^{2} \\ 256 + 256 + {m}^{2} - 32m = 256 + {m}^{2} + 32m \\ 512 + {m}^{2} - 32m = 256 + {m}^{2} + 32m \\ 512 - 256 + {m}^{2} - 32m - {m}^{2} - 32m = 0 \\ 256 - 64m = 0 \\ - 64m = - 256 \\ m = \frac{256}{64} \\ m = 4$

Hope my answer will help you...