Math, asked by soumalya49, 11 months ago


16 - 2 \sqrt{20}  - 2 \sqrt{28}  + 2 \sqrt{35}

Answers

Answered by Kannan0017
1

Answer:

16 -2√20 - 2√28 - 2√35

= 16-2(√(5×4)) - 2(√(7×4)) - 2(√(7×5))

= (16)-(4√5)-(4√7)-(2√35)

= 2{ 8-2√5-2√7-√35}

HOPE YOU UNDERSTAND AND MARK ME AS BRAINLIEST ✌️✌️✌️✌️

Answered by Abdulrazak182
1

Step-by-step explanation:

16 - 2 \sqrt{20}  - 2 \sqrt{28}  + 2 \sqrt{35}  \\=16 - 2 \times 2 \sqrt{5}  - 2 \times 2 \sqrt{7}  + 2 \sqrt{35}  \\  = 16 - 4( \sqrt{5}  +  \sqrt{7} ) + 2 \sqrt{35}

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