Question

$16 {}^{2x} = \frac{1}{128}$

solve the following for x
fast plz​

Answer 1

Answer:

$16^{2x}=\frac{1}{128}$

$(2^4)^{2x}=\frac{1}{2^7}$

$2^{8x}=2^{-7}$

Bases are same

$8x=-7$

$x=\frac{-7}{8}$