Question

$16 {a}^{2} - 25 \div 9a {}^{2}$
pls factorise this question it's urgent pls answer it fast who will answer it first I will mark him brainliest answer​

Answer 1

Answer :

The required factorised form is (4a-\dfrac{5}{2a})(4a+\dfrac{5}{2a})(4a−

2a

5

)(4a+

2a

5

)

Step-by-step explanation:

Since we have given that

16a^2-\dfrac{25}{4a^2}16a

2

−

4a

2

25

We need to factorise the above expression:

As we know that

a^2-b^2=(a-b)(a+b)a

2

−b

2

=(a−b)(a+b)

So, using this, we get that

$$\begin{lgathered}16a^2-\dfrac{25}{4a^2}\\\\=(4a)^2-(\dfrac{5}{2a})^2\\\\=(4a-\dfrac{5}{2a})(4a+\dfrac{5}{2a})\end{lgathered}$$

Hence, the required factorised form is $$(4a-\dfrac{5}{2a})(4a+\dfrac{5}{2a})$$

# learn more:

Factorise: 16a^2 - 25÷ 4a^2