Question

$16(a + b) {}^{2} - 4a - 4b$

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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16 (a + b)² - 4a - 4b


• We factorise it by the method of taking out a common factor


16 (a + b)² - 4a - 4b

= 16 (a + b)² - 4 (a + b)

= 4 (a + b) [ {4(a + b)} - 1]

= 4 (a + b)(4a + 4b - 1)


$<marquee>Hence, the answer is [4 (a + b)(4a + 4b - 1)]. </marquee>$
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Thank you.. ;-)